CAD开发者社区

 找回密码
 立即注册

QQ登录

只需一步,快速开始

ActiveX 开发指南

关于转换对象 (VBA/ActiveX)

2023-1-5 00:50| 发布者: admin| 查看: 758| 评论: 0|来自: AutoCAD

摘要: 使用 TransformBy 方法移动、缩放或旋转给定 4 x 4 转换矩阵的对象。

您可以使用该方法移动、缩放或旋转给定 4 x 4 转换矩阵的对象。TransformBy

下表演示了转换矩阵配置,其中R=旋转和平移

转换矩阵配置
R00 R01 R02 T0
R10 R11 R12 T1
R20 R21 R22 T2
0 0 0 1

要转换对象,请先初始化转换矩阵。下面的示例演示分配给变量的转换矩阵,该矩阵将围绕点 (0, 0, 0) 将实体旋转 90 度:tMatrix

tMatrix(0,0) = 0.0
tMatrix(0,1) = -1.0
tMatrix(0,2) = 0.0
tMatrix(0,3) = 0.0
tMatrix(1,0) = 1.0
tMatrix(1,1) = 0.0
tMatrix(1,2) = 0.0
tMatrix(1,3) = 0.0
tMatrix(2,0) = 0.0
tMatrix(2,1) = 0.0
tMatrix(2,2) = 1.0
tMatrix(2,3) = 0.0
tMatrix(3,0) = 0.0
tMatrix(3,1) = 0.0
tMatrix(3,2) = 0.0
tMatrix(3,3) = 1.0

转换矩阵完成后,使用该方法将矩阵应用于对象。以下代码行演示如何将矩阵 () 应用于对象 ():TransformBytMatrixanObj

anObj.TransformBy tMatrix

使用转换矩阵旋转线条

本示例创建一条线,并使用转换矩阵将其旋转 90 度。

Sub Ch4_TransformBy()
  ' Create a line
  Dim lineObj As AcadLine
  Dim startPt(0 To 2) As Double
  Dim endPt(0 To 2) As Double
  startPt(0) = 2
  startPt(1) = 1
  startPt(2) = 0
  endPt(0) = 5
  endPt(1) = 1
  endPt(2) = 0
  Set lineObj = ThisDrawing.ModelSpace.AddLine(startPt, endPt)
  ZoomAll

  ' Initialize the transMat variable with a
  ' transformation matrix that will rotate
  ' an object by 90 degrees about the point(0,0,0)
  Dim transMat(0 To 3, 0 To 3) As Double
  transMat(0, 0) = 0#: transMat(0, 1) = -1#
  transMat(0, 2) = 0#: transMat(0, 3) = 0#
  transMat(1, 0) = 1#: transMat(1, 1) = 0#
  transMat(1, 2) = 0#: transMat(1, 3) = 0#
  transMat(2, 0) = 0#: transMat(2, 1) = 0#
  transMat(2, 2) = 1#: transMat(2, 3) = 0#
  transMat(3, 0) = 0#: transMat(3, 1) = 0#
  transMat(3, 2) = 0#: transMat(3, 3) = 1#

  ' Transform the line using the defined transformation matrix
  lineObj.TransformBy transMat
  lineObj.Update
End Sub

The following are more examples of transformation matrices:

Rotation Matrix: 90 degrees about point (0, 0, 0)
0.0 -1.0 0.0 0.0
1.0 0.0 0.0 0.0
0.0 0.0 1.0 0.0
0.0 0.0 0.0 1.0
Rotation Matrix: 45 degrees about point (5, 5, 0)
0.707107 -0.707107 0.0 5.0
0.707107 0.707107 0.0 -2.071068
0.0 0.0 1.0 0.0
0.0 0.0 0.0 1.0
Translation Matrix: move an entity by (10, 10, 0)
1.0 0.0 0.0 10.0
0.0 1.0 0.0 10.0
0.0 0.0 1.0 0.0
0.0 0.0 0.0 1.0
缩放矩阵:在点 (0, 0, 0) 处缩放 10,10
10.0 0.0 0.0 0.0
0.0 10.0 0.0 0.0
0.0 0.0 10.0 0.0
0.0 0.0 0.0 1.0
缩放矩阵:在点 (2, 2, 0) 缩放 10,10
10.0 0.0 0.0 -18.0
0.0 10.0 0.0 -18.0
0.0 0.0 10.0 0.0
0.0 0.0 0.0 1.0

路过

雷人

握手

鲜花

鸡蛋

最新评论

QQ|Archiver|CAD开发者社区 ( 苏ICP备2022047690号-1 )

GMT+8, 2024-5-11 22:11

Powered by Discuz! X3.4

Copyright © 2001-2021, Tencent Cloud.

返回顶部